Basket N and Basket P have a total of 42 lollipops. After 3 lollipops were transferred from Basket N to Basket P, there were 6 times as many lollipops in Basket N as Basket P. How many lollipops were there in each basket at first?
- Basket N
- Basket P
|
Basket N |
Basket P |
Total |
Before |
6 u + 3 |
1 u - 3 |
42 |
Change |
- 3 |
+ 3 |
|
After |
6 u |
1 u |
42 |
(a)
The total number of lollipops at first and in the end remains the same.
Total number of lollipops in the end
= 6 u + 1 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
Number of lollipops in Basket N at first
= 6 u + 3
= 6 x 6 + 3
= 36 + 3
= 39
(b)
Number of lollipops in Basket P at first
= 1 u - 3
= 6 - 3
= 3
Answer(s): (a) 39; (b) 3