Bag R and Bag S have a total of 85 chocolate bars. After 15 chocolate bars were transferred from Bag R to Bag S, there were 4 times as many chocolate bars in Bag R as Bag S. How many chocolate bars were there in each bag in the end?
- Bag R
- Bag S
|
Bag R |
Bag S |
Total |
Before |
4 u + 15 |
1 u - 15 |
85 |
Change |
- 15 |
+ 15 |
|
After |
4 u |
1 u |
85 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 4 u + 1 u
= 5 u
5 u = 85
1 u = 85 ÷ 5 = 17
Number of chocolate bars in Bag R in the end
= 4 u
= 4 x 17
= 68
(b)
Number of chocolate bars in Bag S in the end
= 1 u
= 17
Answer(s): (a) 68; (b) 17