Box J and Box K have a total of 120 chocolate bars. After 13 chocolate bars were transferred from Box J to Box K, there were 5 times as many chocolate bars in Box J as Box K. How many chocolate bars were there in each box in the end?
- Box J
- Box K
|
Box J |
Box K |
Total |
Before |
5 u + 13 |
1 u - 13 |
120 |
Change |
- 13 |
+ 13 |
|
After |
5 u |
1 u |
120 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 5 u + 1 u
= 6 u
6 u = 120
1 u = 120 ÷ 6 = 20
Number of chocolate bars in Box J in the end
= 5 u
= 5 x 20
= 100
(b)
Number of chocolate bars in Box K in the end
= 1 u
= 20
Answer(s): (a) 100; (b) 20