Bag U and Bag V have a total of 60 jelly beans. After 5 jelly beans were transferred from Bag U to Bag V, there were 4 times as many jelly beans in Bag U as Bag V. How many jelly beans were there in each bag at first?
- Bag U
- Bag V
|
Bag U |
Bag V |
Total |
Before |
4 u + 5 |
1 u - 5 |
60 |
Change |
- 5 |
+ 5 |
|
After |
4 u |
1 u |
60 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 4 u + 1 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of jelly beans in Bag U at first
= 4 u + 5
= 4 x 12 + 5
= 48 + 5
= 53
(b)
Number of jelly beans in Bag V at first
= 1 u - 5
= 12 - 5
= 7
Answer(s): (a) 53; (b) 7