Basket R and Basket S have a total of 133 jelly beans. After 5 jelly beans were transferred from Basket R to Basket S, there were 6 times as many jelly beans in Basket R as Basket S. How many jelly beans were there in each basket at first?
- Basket R
- Basket S
|
Basket R |
Basket S |
Total |
Before |
6 u + 5 |
1 u - 5 |
133 |
Change |
- 5 |
+ 5 |
|
After |
6 u |
1 u |
133 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 6 u + 1 u
= 7 u
7 u = 133
1 u = 133 ÷ 7 = 19
Number of jelly beans in Basket R at first
= 6 u + 5
= 6 x 19 + 5
= 114 + 5
= 119
(b)
Number of jelly beans in Basket S at first
= 1 u - 5
= 19 - 5
= 14
Answer(s): (a) 119; (b) 14