Bag H and Bag J have a total of 120 jelly beans. After 16 jelly beans were transferred from Bag H to Bag J, there were 5 times as many jelly beans in Bag H as Bag J. How many jelly beans were there in each bag in the end?
- Bag H
- Bag J
|
Bag H |
Bag J |
Total |
Before |
5 u + 16 |
1 u - 16 |
120 |
Change |
- 16 |
+ 16 |
|
After |
5 u |
1 u |
120 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 5 u + 1 u
= 6 u
6 u = 120
1 u = 120 ÷ 6 = 20
Number of jelly beans in Bag H in the end
= 5 u
= 5 x 20
= 100
(b)
Number of jelly beans in Bag J in the end
= 1 u
= 20
Answer(s): (a) 100; (b) 20