Bag V and Bag W have a total of 65 lollipops. After 7 lollipops were transferred from Bag V to Bag W, there were 4 times as many lollipops in Bag V as Bag W. How many lollipops were there in each bag at first?
- Bag V
- Bag W
|
Bag V |
Bag W |
Total |
Before |
4 u + 7 |
1 u - 7 |
65 |
Change |
- 7 |
+ 7 |
|
After |
4 u |
1 u |
65 |
(a)
The total number of lollipops at first and in the end remains the same.
Total number of lollipops in the end
= 4 u + 1 u
= 5 u
5 u = 65
1 u = 65 ÷ 5 = 13
Number of lollipops in Bag V at first
= 4 u + 7
= 4 x 13 + 7
= 52 + 7
= 59
(b)
Number of lollipops in Bag W at first
= 1 u - 7
= 13 - 7
= 6
Answer(s): (a) 59; (b) 6