Box G and Box H have a total of 114 candy canes. After 13 candy canes were transferred from Box G to Box H, there were 5 times as many candy canes in Box G as Box H. How many candy canes were there in each box in the end?
- Box G
- Box H
|
Box G |
Box H |
Total |
Before |
5 u + 13 |
1 u - 13 |
114 |
Change |
- 13 |
+ 13 |
|
After |
5 u |
1 u |
114 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 114
1 u = 114 ÷ 6 = 19
Number of candy canes in Box G in the end
= 5 u
= 5 x 19
= 95
(b)
Number of candy canes in Box H in the end
= 1 u
= 19
Answer(s): (a) 95; (b) 19