Box P and Box Q have a total of 56 candy canes. After 5 candy canes were transferred from Box P to Box Q, there were 6 times as many candy canes in Box P as Box Q. How many candy canes were there in each box at first?
- Box P
- Box Q
|
Box P |
Box Q |
Total |
Before |
6 u + 5 |
1 u - 5 |
56 |
Change |
- 5 |
+ 5 |
|
After |
6 u |
1 u |
56 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 56
1 u = 56 ÷ 7 = 8
Number of candy canes in Box P at first
= 6 u + 5
= 6 x 8 + 5
= 48 + 5
= 53
(b)
Number of candy canes in Box Q at first
= 1 u - 5
= 8 - 5
= 3
Answer(s): (a) 53; (b) 3