Bag V and Bag W have a total of 140 chocolate bars. After 13 chocolate bars were transferred from Bag V to Bag W, there were 6 times as many chocolate bars in Bag V as Bag W. How many chocolate bars were there in each bag at first?
- Bag V
- Bag W
| |
Bag V |
Bag W |
Total |
| Before |
6 u + 13 |
1 u - 13 |
140 |
| Change |
- 13 |
+ 13 |
|
| After |
6 u |
1 u |
140 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 6 u + 1 u
= 7 u
7 u = 140
1 u = 140 ÷ 7 = 20
Number of chocolate bars in Bag V at first
= 6 u + 13
= 6 x 20 + 13
= 120 + 13
= 133
(b)
Number of chocolate bars in Bag W at first
= 1 u - 13
= 20 - 13
= 7
Answer(s): (a) 133; (b) 7
