Basket K and Basket L have a total of 120 lollipops. After 2 lollipops were transferred from Basket K to Basket L, there were 5 times as many lollipops in Basket K as Basket L. How many lollipops were there in each basket at first?
- Basket K
- Basket L
|
Basket K |
Basket L |
Total |
Before |
5 u + 2 |
1 u - 2 |
120 |
Change |
- 2 |
+ 2 |
|
After |
5 u |
1 u |
120 |
(a)
The total number of lollipops at first and in the end remains the same.
Total number of lollipops in the end
= 5 u + 1 u
= 6 u
6 u = 120
1 u = 120 ÷ 6 = 20
Number of lollipops in Basket K at first
= 5 u + 2
= 5 x 20 + 2
= 100 + 2
= 102
(b)
Number of lollipops in Basket L at first
= 1 u - 2
= 20 - 2
= 18
Answer(s): (a) 102; (b) 18