Bag P and Bag Q have a total of 119 jelly beans. After 14 jelly beans were transferred from Bag P to Bag Q, there were 6 times as many jelly beans in Bag P as Bag Q. How many jelly beans were there in each bag at first?
- Bag P
- Bag Q
| |
Bag P |
Bag Q |
Total |
| Before |
6 u + 14 |
1 u - 14 |
119 |
| Change |
- 14 |
+ 14 |
|
| After |
6 u |
1 u |
119 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 6 u + 1 u
= 7 u
7 u = 119
1 u = 119 ÷ 7 = 17
Number of jelly beans in Bag P at first
= 6 u + 14
= 6 x 17 + 14
= 102 + 14
= 116
(b)
Number of jelly beans in Bag Q at first
= 1 u - 14
= 17 - 14
= 3
Answer(s): (a) 116; (b) 3
