Bag H and Bag J have a total of 76 jelly beans. After 17 jelly beans were transferred from Bag H to Bag J, there were 3 times as many jelly beans in Bag H as Bag J. How many jelly beans were there in each bag at first?
- Bag H
- Bag J
| |
Bag H |
Bag J |
Total |
| Before |
3 u + 17 |
1 u - 17 |
76 |
| Change |
- 17 |
+ 17 |
|
| After |
3 u |
1 u |
76 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 3 u + 1 u
= 4 u
4 u = 76
1 u = 76 ÷ 4 = 19
Number of jelly beans in Bag H at first
= 3 u + 17
= 3 x 19 + 17
= 57 + 17
= 74
(b)
Number of jelly beans in Bag J at first
= 1 u - 17
= 19 - 17
= 2
Answer(s): (a) 74; (b) 2
