Basket A and Basket B have a total of 84 candy canes. After 12 candy canes were transferred from Basket A to Basket B, there were 5 times as many candy canes in Basket A as Basket B. How many candy canes were there in each basket at first?
- Basket A
- Basket B
|
Basket A |
Basket B |
Total |
Before |
5 u + 12 |
1 u - 12 |
84 |
Change |
- 12 |
+ 12 |
|
After |
5 u |
1 u |
84 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 84
1 u = 84 ÷ 6 = 14
Number of candy canes in Basket A at first
= 5 u + 12
= 5 x 14 + 12
= 70 + 12
= 82
(b)
Number of candy canes in Basket B at first
= 1 u - 12
= 14 - 12
= 2
Answer(s): (a) 82; (b) 2