Bag G and Bag H have a total of 76 jelly beans. After 3 jelly beans were transferred from Bag G to Bag H, there were 3 times as many jelly beans in Bag G as Bag H. How many jelly beans were there in each bag at first?
- Bag G
- Bag H
|
Bag G |
Bag H |
Total |
Before |
3 u + 3 |
1 u - 3 |
76 |
Change |
- 3 |
+ 3 |
|
After |
3 u |
1 u |
76 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 3 u + 1 u
= 4 u
4 u = 76
1 u = 76 ÷ 4 = 19
Number of jelly beans in Bag G at first
= 3 u + 3
= 3 x 19 + 3
= 57 + 3
= 60
(b)
Number of jelly beans in Bag H at first
= 1 u - 3
= 19 - 3
= 16
Answer(s): (a) 60; (b) 16