Basket N and Basket P have a total of 36 candy canes. After 2 candy canes were transferred from Basket N to Basket P, there were 5 times as many candy canes in Basket N as Basket P. How many candy canes were there in each basket at first?
- Basket N
- Basket P
|
Basket N |
Basket P |
Total |
Before |
5 u + 2 |
1 u - 2 |
36 |
Change |
- 2 |
+ 2 |
|
After |
5 u |
1 u |
36 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 36
1 u = 36 ÷ 6 = 6
Number of candy canes in Basket N at first
= 5 u + 2
= 5 x 6 + 2
= 30 + 2
= 32
(b)
Number of candy canes in Basket P at first
= 1 u - 2
= 6 - 2
= 4
Answer(s): (a) 32; (b) 4