Basket J and Basket K have a total of 95 jelly beans. After 11 jelly beans were transferred from Basket J to Basket K, there were 4 times as many jelly beans in Basket J as Basket K. How many jelly beans were there in each basket in the end?
- Basket J
- Basket K
|
Basket J |
Basket K |
Total |
Before |
4 u + 11 |
1 u - 11 |
95 |
Change |
- 11 |
+ 11 |
|
After |
4 u |
1 u |
95 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 4 u + 1 u
= 5 u
5 u = 95
1 u = 95 ÷ 5 = 19
Number of jelly beans in Basket J in the end
= 4 u
= 4 x 19
= 76
(b)
Number of jelly beans in Basket K in the end
= 1 u
= 19
Answer(s): (a) 76; (b) 19