Basket E and Basket F have a total of 40 candy canes. After 2 candy canes were transferred from Basket E to Basket F, there were 4 times as many candy canes in Basket E as Basket F. How many candy canes were there in each basket in the end?
- Basket E
- Basket F
|
Basket E |
Basket F |
Total |
Before |
4 u + 2 |
1 u - 2 |
40 |
Change |
- 2 |
+ 2 |
|
After |
4 u |
1 u |
40 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 4 u + 1 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of candy canes in Basket E in the end
= 4 u
= 4 x 8
= 32
(b)
Number of candy canes in Basket F in the end
= 1 u
= 8
Answer(s): (a) 32; (b) 8