Bag E and Bag F have a total of 42 lollipops. After 3 lollipops were transferred from Bag E to Bag F, there were 6 times as many lollipops in Bag E as Bag F. How many lollipops were there in each bag in the end?
- Bag E
- Bag F
|
Bag E |
Bag F |
Total |
Before |
6 u + 3 |
1 u - 3 |
42 |
Change |
- 3 |
+ 3 |
|
After |
6 u |
1 u |
42 |
(a)
The total number of lollipops at first and in the end remains the same.
Total number of lollipops in the end
= 6 u + 1 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
Number of lollipops in Bag E in the end
= 6 u
= 6 x 6
= 36
(b)
Number of lollipops in Bag F in the end
= 1 u
= 6
Answer(s): (a) 36; (b) 6