Bag L and Bag M have a total of 108 sweets. After 9 sweets were transferred from Bag L to Bag M, there were 5 times as many sweets in Bag L as Bag M. How many sweets were there in each bag in the end?
- Bag L
- Bag M
|
Bag L |
Bag M |
Total |
Before |
5 u + 9 |
1 u - 9 |
108 |
Change |
- 9 |
+ 9 |
|
After |
5 u |
1 u |
108 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 5 u + 1 u
= 6 u
6 u = 108
1 u = 108 ÷ 6 = 18
Number of sweets in Bag L in the end
= 5 u
= 5 x 18
= 90
(b)
Number of sweets in Bag M in the end
= 1 u
= 18
Answer(s): (a) 90; (b) 18