Basket H and Basket J have a total of 90 sweets. After 9 sweets were transferred from Basket H to Basket J, there were 5 times as many sweets in Basket H as Basket J. How many sweets were there in each basket at first?
- Basket H
- Basket J
|
Basket H |
Basket J |
Total |
Before |
5 u + 9 |
1 u - 9 |
90 |
Change |
- 9 |
+ 9 |
|
After |
5 u |
1 u |
90 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 5 u + 1 u
= 6 u
6 u = 90
1 u = 90 ÷ 6 = 15
Number of sweets in Basket H at first
= 5 u + 9
= 5 x 15 + 9
= 75 + 9
= 84
(b)
Number of sweets in Basket J at first
= 1 u - 9
= 15 - 9
= 6
Answer(s): (a) 84; (b) 6