Basket C and Basket D have a total of 102 jelly beans. After 14 jelly beans were transferred from Basket C to Basket D, there were 5 times as many jelly beans in Basket C as Basket D. How many jelly beans were there in each basket at first?
- Basket C
- Basket D
|
Basket C |
Basket D |
Total |
Before |
5 u + 14 |
1 u - 14 |
102 |
Change |
- 14 |
+ 14 |
|
After |
5 u |
1 u |
102 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 5 u + 1 u
= 6 u
6 u = 102
1 u = 102 ÷ 6 = 17
Number of jelly beans in Basket C at first
= 5 u + 14
= 5 x 17 + 14
= 85 + 14
= 99
(b)
Number of jelly beans in Basket D at first
= 1 u - 14
= 17 - 14
= 3
Answer(s): (a) 99; (b) 3