Bag L and Bag M have a total of 75 chocolate bars. After 2 chocolate bars were transferred from Bag L to Bag M, there were 4 times as many chocolate bars in Bag L as Bag M. How many chocolate bars were there in each bag at first?
- Bag L
- Bag M
|
Bag L |
Bag M |
Total |
Before |
4 u + 2 |
1 u - 2 |
75 |
Change |
- 2 |
+ 2 |
|
After |
4 u |
1 u |
75 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 4 u + 1 u
= 5 u
5 u = 75
1 u = 75 ÷ 5 = 15
Number of chocolate bars in Bag L at first
= 4 u + 2
= 4 x 15 + 2
= 60 + 2
= 62
(b)
Number of chocolate bars in Bag M at first
= 1 u - 2
= 15 - 2
= 13
Answer(s): (a) 62; (b) 13