Bag P and Bag Q have a total of 72 jelly beans. After 10 jelly beans were transferred from Bag P to Bag Q, there were 3 times as many jelly beans in Bag P as Bag Q. How many jelly beans were there in each bag at first?
- Bag P
- Bag Q
|
Bag P |
Bag Q |
Total |
Before |
3 u + 10 |
1 u - 10 |
72 |
Change |
- 10 |
+ 10 |
|
After |
3 u |
1 u |
72 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 3 u + 1 u
= 4 u
4 u = 72
1 u = 72 ÷ 4 = 18
Number of jelly beans in Bag P at first
= 3 u + 10
= 3 x 18 + 10
= 54 + 10
= 64
(b)
Number of jelly beans in Bag Q at first
= 1 u - 10
= 18 - 10
= 8
Answer(s): (a) 64; (b) 8