Bag K and Bag L have a total of 112 sweets. After 2 sweets were transferred from Bag K to Bag L, there were 6 times as many sweets in Bag K as Bag L. How many sweets were there in each bag at first?
- Bag K
- Bag L
|
Bag K |
Bag L |
Total |
Before |
6 u + 2 |
1 u - 2 |
112 |
Change |
- 2 |
+ 2 |
|
After |
6 u |
1 u |
112 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 6 u + 1 u
= 7 u
7 u = 112
1 u = 112 ÷ 7 = 16
Number of sweets in Bag K at first
= 6 u + 2
= 6 x 16 + 2
= 96 + 2
= 98
(b)
Number of sweets in Bag L at first
= 1 u - 2
= 16 - 2
= 14
Answer(s): (a) 98; (b) 14