Basket X and Basket Y have a total of 108 sweets. After 6 sweets were transferred from Basket X to Basket Y, there were 5 times as many sweets in Basket X as Basket Y. How many sweets were there in each basket at first?
- Basket X
- Basket Y
|
Basket X |
Basket Y |
Total |
Before |
5 u + 6 |
1 u - 6 |
108 |
Change |
- 6 |
+ 6 |
|
After |
5 u |
1 u |
108 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 5 u + 1 u
= 6 u
6 u = 108
1 u = 108 ÷ 6 = 18
Number of sweets in Basket X at first
= 5 u + 6
= 5 x 18 + 6
= 90 + 6
= 96
(b)
Number of sweets in Basket Y at first
= 1 u - 6
= 18 - 6
= 12
Answer(s): (a) 96; (b) 12