Basket V and Basket W have a total of 112 candy canes. After 7 candy canes were transferred from Basket V to Basket W, there were 6 times as many candy canes in Basket V as Basket W. How many candy canes were there in each basket in the end?
- Basket V
- Basket W
|
Basket V |
Basket W |
Total |
Before |
6 u + 7 |
1 u - 7 |
112 |
Change |
- 7 |
+ 7 |
|
After |
6 u |
1 u |
112 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 112
1 u = 112 ÷ 7 = 16
Number of candy canes in Basket V in the end
= 6 u
= 6 x 16
= 96
(b)
Number of candy canes in Basket W in the end
= 1 u
= 16
Answer(s): (a) 96; (b) 16