Box S and Box T have a total of 36 candy canes. After 4 candy canes were transferred from Box S to Box T, there were 5 times as many candy canes in Box S as Box T. How many candy canes were there in each box in the end?
- Box S
- Box T
|
Box S |
Box T |
Total |
Before |
5 u + 4 |
1 u - 4 |
36 |
Change |
- 4 |
+ 4 |
|
After |
5 u |
1 u |
36 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 36
1 u = 36 ÷ 6 = 6
Number of candy canes in Box S in the end
= 5 u
= 5 x 6
= 30
(b)
Number of candy canes in Box T in the end
= 1 u
= 6
Answer(s): (a) 30; (b) 6