Box F and Box G have a total of 140 candy canes. After 2 candy canes were transferred from Box F to Box G, there were 6 times as many candy canes in Box F as Box G. How many candy canes were there in each box at first?
- Box F
- Box G
| |
Box F |
Box G |
Total |
| Before |
6 u + 2 |
1 u - 2 |
140 |
| Change |
- 2 |
+ 2 |
|
| After |
6 u |
1 u |
140 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 140
1 u = 140 ÷ 7 = 20
Number of candy canes in Box F at first
= 6 u + 2
= 6 x 20 + 2
= 120 + 2
= 122
(b)
Number of candy canes in Box G at first
= 1 u - 2
= 20 - 2
= 18
Answer(s): (a) 122; (b) 18
