Basket D and Basket E have a total of 84 candy canes. After 5 candy canes were transferred from Basket D to Basket E, there were 5 times as many candy canes in Basket D as Basket E. How many candy canes were there in each basket at first?
- Basket D
- Basket E
|
Basket D |
Basket E |
Total |
Before |
5 u + 5 |
1 u - 5 |
84 |
Change |
- 5 |
+ 5 |
|
After |
5 u |
1 u |
84 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 84
1 u = 84 ÷ 6 = 14
Number of candy canes in Basket D at first
= 5 u + 5
= 5 x 14 + 5
= 70 + 5
= 75
(b)
Number of candy canes in Basket E at first
= 1 u - 5
= 14 - 5
= 9
Answer(s): (a) 75; (b) 9