Box C and Box D have a total of 63 candy canes. After 3 candy canes were transferred from Box C to Box D, there were 6 times as many candy canes in Box C as Box D. How many candy canes were there in each box in the end?
- Box C
- Box D
|
Box C |
Box D |
Total |
Before |
6 u + 3 |
1 u - 3 |
63 |
Change |
- 3 |
+ 3 |
|
After |
6 u |
1 u |
63 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 63
1 u = 63 ÷ 7 = 9
Number of candy canes in Box C in the end
= 6 u
= 6 x 9
= 54
(b)
Number of candy canes in Box D in the end
= 1 u
= 9
Answer(s): (a) 54; (b) 9