Bag Y and Bag Z have a total of 100 chocolate bars. After 6 chocolate bars were transferred from Bag Y to Bag Z, there were 4 times as many chocolate bars in Bag Y as Bag Z. How many chocolate bars were there in each bag in the end?
- Bag Y
- Bag Z
|
Bag Y |
Bag Z |
Total |
Before |
4 u + 6 |
1 u - 6 |
100 |
Change |
- 6 |
+ 6 |
|
After |
4 u |
1 u |
100 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 4 u + 1 u
= 5 u
5 u = 100
1 u = 100 ÷ 5 = 20
Number of chocolate bars in Bag Y in the end
= 4 u
= 4 x 20
= 80
(b)
Number of chocolate bars in Bag Z in the end
= 1 u
= 20
Answer(s): (a) 80; (b) 20