Box G and Box H have a total of 84 candy canes. After 3 candy canes were transferred from Box G to Box H, there were 5 times as many candy canes in Box G as Box H. How many candy canes were there in each box at first?
- Box G
- Box H
|
Box G |
Box H |
Total |
Before |
5 u + 3 |
1 u - 3 |
84 |
Change |
- 3 |
+ 3 |
|
After |
5 u |
1 u |
84 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 84
1 u = 84 ÷ 6 = 14
Number of candy canes in Box G at first
= 5 u + 3
= 5 x 14 + 3
= 70 + 3
= 73
(b)
Number of candy canes in Box H at first
= 1 u - 3
= 14 - 3
= 11
Answer(s): (a) 73; (b) 11