Bag V and Bag W have a total of 50 chocolate bars. After 6 chocolate bars were transferred from Bag V to Bag W, there were 4 times as many chocolate bars in Bag V as Bag W. How many chocolate bars were there in each bag at first?
- Bag V
- Bag W
|
Bag V |
Bag W |
Total |
Before |
4 u + 6 |
1 u - 6 |
50 |
Change |
- 6 |
+ 6 |
|
After |
4 u |
1 u |
50 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 4 u + 1 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of chocolate bars in Bag V at first
= 4 u + 6
= 4 x 10 + 6
= 40 + 6
= 46
(b)
Number of chocolate bars in Bag W at first
= 1 u - 6
= 10 - 6
= 4
Answer(s): (a) 46; (b) 4