Bag K and Bag L have a total of 114 sweets. After 17 sweets were transferred from Bag K to Bag L, there were 5 times as many sweets in Bag K as Bag L. How many sweets were there in each bag in the end?
- Bag K
- Bag L
|
Bag K |
Bag L |
Total |
Before |
5 u + 17 |
1 u - 17 |
114 |
Change |
- 17 |
+ 17 |
|
After |
5 u |
1 u |
114 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 5 u + 1 u
= 6 u
6 u = 114
1 u = 114 ÷ 6 = 19
Number of sweets in Bag K in the end
= 5 u
= 5 x 19
= 95
(b)
Number of sweets in Bag L in the end
= 1 u
= 19
Answer(s): (a) 95; (b) 19