Box Y and Box Z have a total of 108 lollipops. After 8 lollipops were transferred from Box Y to Box Z, there were 5 times as many lollipops in Box Y as Box Z. How many lollipops were there in each box at first?
- Box Y
- Box Z
|
Box Y |
Box Z |
Total |
Before |
5 u + 8 |
1 u - 8 |
108 |
Change |
- 8 |
+ 8 |
|
After |
5 u |
1 u |
108 |
(a)
The total number of lollipops at first and in the end remains the same.
Total number of lollipops in the end
= 5 u + 1 u
= 6 u
6 u = 108
1 u = 108 ÷ 6 = 18
Number of lollipops in Box Y at first
= 5 u + 8
= 5 x 18 + 8
= 90 + 8
= 98
(b)
Number of lollipops in Box Z at first
= 1 u - 8
= 18 - 8
= 10
Answer(s): (a) 98; (b) 10