Bag A and Bag B have a total of 105 sweets. After 5 sweets were transferred from Bag A to Bag B, there were 6 times as many sweets in Bag A as Bag B. How many sweets were there in each bag in the end?
- Bag A
- Bag B
|
Bag A |
Bag B |
Total |
Before |
6 u + 5 |
1 u - 5 |
105 |
Change |
- 5 |
+ 5 |
|
After |
6 u |
1 u |
105 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 6 u + 1 u
= 7 u
7 u = 105
1 u = 105 ÷ 7 = 15
Number of sweets in Bag A in the end
= 6 u
= 6 x 15
= 90
(b)
Number of sweets in Bag B in the end
= 1 u
= 15
Answer(s): (a) 90; (b) 15