George had 6 times as many coins as Jeremy at first. Then each of them bought an equal number of new coins. In the end, Jeremy had 55 coins and George had 3 times as many coins as Jeremy. How many coins did both of them buy altogether?
| |
George |
Jeremy |
Difference |
| Before |
6x2 =
12 u |
1x2 =
2 u |
5x2 =
10 u |
| Change |
+ ? |
+ ? |
|
| After |
3x5 =
15 u |
1x5 =
5 u |
2x5 =
10 u |
The difference in the number of coins at first and in the end remains unchanged. Make the difference in the number of coins at first and in the end the same. LCM of 5 and 2 is 10.
Number of coins that Jeremy had in the end = 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Number of coins that George bought
= 15 u - 12 u
= 3 u
Number of coins that both of them bought altogether
= 2 x 3 u
= 6 u
= 6 x 11
= 66
Answer(s): 66
