Simon had 5 times as many stickers as Fabian at first. Then each of them bought an equal number of new stickers. In the end, Fabian had 10 stickers and Simon had 3 times as many stickers as Fabian. How many stickers did both of them buy altogether?
| |
Simon |
Fabian |
Difference |
| Before |
5x1 =
5 u |
1x1 =
1 u |
4x1 =
4 u |
| Change |
+ ? |
+ ? |
|
| After |
3x2 =
6 u |
1x2 =
2 u |
2x2 =
4 u |
The difference in the number of stickers at first and in the end remains unchanged. Make the difference in the number of stickers at first and in the end the same. LCM of 4 and 2 is 4.
Number of stickers that Fabian had in the end = 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of stickers that Simon bought
= 6 u - 5 u
= 1 u
Number of stickers that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 5
= 10
Answer(s): 10
