Carl had 6 times as many beads as Ethan at first. Then each of them bought an equal number of new beads. In the end, Ethan had 60 beads and Carl had 5 times as many beads as Ethan. How many beads did both of them buy altogether?
| |
Carl |
Ethan |
Difference |
| Before |
6x4 =
24 u |
1x4 =
4 u |
5x4 =
20 u |
| Change |
+ ? |
+ ? |
|
| After |
5x5 =
25 u |
1x5 =
5 u |
4x5 =
20 u |
The difference in the number of beads at first and in the end remains unchanged. Make the difference in the number of beads at first and in the end the same. LCM of 5 and 4 is 20.
Number of beads that Ethan had in the end = 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of beads that Carl bought
= 25 u - 24 u
= 1 u
Number of beads that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 12
= 24
Answer(s): 24
