Cody had 4 times as many cards as Jenson at first. Then each of them bought an equal number of new cards. In the end, Jenson had 12 cards and Cody had 3 times as many cards as Jenson. How many cards did both of them buy altogether?
| |
Cody |
Jenson |
Difference |
| Before |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change |
+ ? |
+ ? |
|
| After |
3x3 =
9 u |
1x3 =
3 u |
2x3 =
6 u |
The difference in the number of cards at first and in the end remains unchanged. Make the difference in the number of cards at first and in the end the same. LCM of 3 and 2 is 6.
Number of cards that Jenson had in the end = 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of cards that Cody bought
= 9 u - 8 u
= 1 u
Number of cards that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
