Asher had 6 times as many beads as Perry at first. Then each of them bought an equal number of new beads. In the end, Perry had 10 beads and Asher had 3 times as many beads as Perry. How many beads did both of them buy altogether?
| |
Asher |
Perry |
Difference |
| Before |
6x2 =
12 u |
1x2 =
2 u |
5x2 =
10 u |
| Change |
+ ? |
+ ? |
|
| After |
3x5 =
15 u |
1x5 =
5 u |
2x5 =
10 u |
The difference in the number of beads at first and in the end remains unchanged. Make the difference in the number of beads at first and in the end the same. LCM of 5 and 2 is 10.
Number of beads that Perry had in the end = 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of beads that Asher bought
= 15 u - 12 u
= 3 u
Number of beads that both of them bought altogether
= 2 x 3 u
= 6 u
= 6 x 2
= 12
Answer(s): 12
