Ahmad had 5 times as many stickers as Rael at first. Then each of them bought an equal number of new stickers. In the end, Rael had 8 stickers and Ahmad had 3 times as many stickers as Rael. How many stickers did both of them buy altogether?
| |
Ahmad |
Rael |
Difference |
| Before |
5x1 =
5 u |
1x1 =
1 u |
4x1 =
4 u |
| Change |
+ ? |
+ ? |
|
| After |
3x2 =
6 u |
1x2 =
2 u |
2x2 =
4 u |
The difference in the number of stickers at first and in the end remains unchanged. Make the difference in the number of stickers at first and in the end the same. LCM of 4 and 2 is 4.
Number of stickers that Rael had in the end = 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Number of stickers that Ahmad bought
= 6 u - 5 u
= 1 u
Number of stickers that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
