Tim had 4 times as many beads as Liam at first. Then each of them bought an equal number of new beads. In the end, Liam had 12 beads and Tim had 3 times as many beads as Liam. How many beads did both of them buy altogether?
| |
Tim |
Liam |
Difference |
| Before |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change |
+ ? |
+ ? |
|
| After |
3x3 =
9 u |
1x3 =
3 u |
2x3 =
6 u |
The difference in the number of beads at first and in the end remains unchanged. Make the difference in the number of beads at first and in the end the same. LCM of 3 and 2 is 6.
Number of beads that Liam had in the end = 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of beads that Tim bought
= 9 u - 8 u
= 1 u
Number of beads that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
