Luis had 4 times as many marbles as Valen at first. Then each of them bought an equal number of new marbles. In the end, Valen had 12 marbles and Luis had 3 times as many marbles as Valen. How many marbles did both of them buy altogether?
| |
Luis |
Valen |
Difference |
| Before |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change |
+ ? |
+ ? |
|
| After |
3x3 =
9 u |
1x3 =
3 u |
2x3 =
6 u |
The difference in the number of marbles at first and in the end remains unchanged. Make the difference in the number of marbles at first and in the end the same. LCM of 3 and 2 is 6.
Number of marbles that Valen had in the end = 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of marbles that Luis bought
= 9 u - 8 u
= 1 u
Number of marbles that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
