Ivan had 6 times as many beads as George at first. Then each of them bought an equal number of new beads. In the end, George had 25 beads and Ivan had 5 times as many beads as George. How many beads did both of them buy altogether?
| |
Ivan |
George |
Difference |
| Before |
6x4 =
24 u |
1x4 =
4 u |
5x4 =
20 u |
| Change |
+ ? |
+ ? |
|
| After |
5x5 =
25 u |
1x5 =
5 u |
4x5 =
20 u |
The difference in the number of beads at first and in the end remains unchanged. Make the difference in the number of beads at first and in the end the same. LCM of 5 and 4 is 20.
Number of beads that George had in the end = 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of beads that Ivan bought
= 25 u - 24 u
= 1 u
Number of beads that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 5
= 10
Answer(s): 10
