Nick had 5 times as many cards as Luis at first. Then each of them bought an equal number of new cards. In the end, Luis had 48 cards and Nick had 4 times as many cards as Luis. How many cards did both of them buy altogether?
| |
Nick |
Luis |
Difference |
| Before |
5x3 =
15 u |
1x3 =
3 u |
4x3 =
12 u |
| Change |
+ ? |
+ ? |
|
| After |
4x4 =
16 u |
1x4 =
4 u |
3x4 =
12 u |
The difference in the number of cards at first and in the end remains unchanged. Make the difference in the number of cards at first and in the end the same. LCM of 4 and 3 is 12.
Number of cards that Luis had in the end = 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Number of cards that Nick bought
= 16 u - 15 u
= 1 u
Number of cards that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 12
= 24
Answer(s): 24
