Archie had 5 times as many beads as Dylan at first. Then each of them bought an equal number of new beads. In the end, Dylan had 12 beads and Archie had 4 times as many beads as Dylan. How many beads did both of them buy altogether?
| |
Archie |
Dylan |
Difference |
| Before |
5x3 =
15 u |
1x3 =
3 u |
4x3 =
12 u |
| Change |
+ ? |
+ ? |
|
| After |
4x4 =
16 u |
1x4 =
4 u |
3x4 =
12 u |
The difference in the number of beads at first and in the end remains unchanged. Make the difference in the number of beads at first and in the end the same. LCM of 4 and 3 is 12.
Number of beads that Dylan had in the end = 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of beads that Archie bought
= 16 u - 15 u
= 1 u
Number of beads that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 3
= 6
Answer(s): 6
