Fred had 6 times as many stickers as Seth at first. Then each of them bought an equal number of new stickers. In the end, Seth had 45 stickers and Fred had 4 times as many stickers as Seth. How many stickers did both of them buy altogether?
| |
Fred |
Seth |
Difference |
| Before |
6x3 =
18 u |
1x3 =
3 u |
5x3 =
15 u |
| Change |
+ ? |
+ ? |
|
| After |
4x5 =
20 u |
1x5 =
5 u |
3x5 =
15 u |
The difference in the number of stickers at first and in the end remains unchanged. Make the difference in the number of stickers at first and in the end the same. LCM of 5 and 3 is 15.
Number of stickers that Seth had in the end = 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Number of stickers that Fred bought
= 20 u - 18 u
= 2 u
Number of stickers that both of them bought altogether
= 2 x 2 u
= 4 u
= 4 x 9
= 36
Answer(s): 36
