Cody had 4 times as many buttons as Fred at first. Then each of them bought an equal number of new buttons. In the end, Fred had 33 buttons and Cody had 3 times as many buttons as Fred. How many buttons did both of them buy altogether?
| |
Cody |
Fred |
Difference |
| Before |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change |
+ ? |
+ ? |
|
| After |
3x3 =
9 u |
1x3 =
3 u |
2x3 =
6 u |
The difference in the number of buttons at first and in the end remains unchanged. Make the difference in the number of buttons at first and in the end the same. LCM of 3 and 2 is 6.
Number of buttons that Fred had in the end = 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Number of buttons that Cody bought
= 9 u - 8 u
= 1 u
Number of buttons that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 11
= 22
Answer(s): 22
